I have been considering the classic water bending experiment with a charged
rod and stream of water. I have a simple question: would it be possible to
use this effect to make the water run in a complete circle around the
charged rod?
Thinking about the forces required for circular motion, a centripetal
force
and a tangential force, -could the tangential force be provided by the
pressure of the water "jet", and the centripetal force be provided by the
charged rod?
Considering a horizontal plane with no gravity acting:
In order to work out the centripetal force ive got:
F=mV^2/r
F centripetal force
m mass
V water jet velocity
r radius
so express m as a flow rate:
F/t=MV^2/r
t time
M mass flow rate
so for a flow rate of say 0.005 litre per second, through an orifice of
1mm^2:
V= 5 metres per second
so at a radius of 50mm
F = 0.005 x 25 / 0.05
F= 2.5N
This seems quite high, would it be possible to produce this magnitude of
force from a charged rod of some description - possibly augmented by a
high
voltage supply? Or would breakdown occur?
Applying Coulombs Law then:
F=kQq/r^2
k, and r are known,
How can I go about quantifying Q and q?
I know water is a polar liquid, and a quantity of water has no net charge,
but I know the ratio of hydrogen and oxygen atoms in a water molecule.
I also know that 1kg of water contains 3.34 x10^25 molecules (?right?)
So if I knew the charge on each of a hydrogen and oxygen molecule could I
work out the charge available when polarised? Is that right or am I
barking
up the wrong tree?
Many thanks for any help at all,
|
