"Manfred" <mmornhin@[EMAIL PROTECTED]
> writes:
> Hi Randy,
>
>>I have the advantage of seeing the other posters' suggestions and
>>your repsonse,
>
> For some reason my follow-up ended up posted as a new thread! I don't
know
> if I pressed the wrong button, or if it happened for some other reason.
So
> now we have two threads with this...
>
>> but how about the following:
>>
>> y[n] = x[n] - 0.61803 * x[n-1] + x[n-2]
>>
>>? This is an FIR notch filter with a notch right at 20 Hz.
>>The 0.61803 term is 2*cos(0.4*pi).
>
> But I don't need a notch filter! I need a low pass... Anyway, it's
> interesting!
Hi Manfred,
I thought what you needed was to get rid of the 20 Hz interference. Is
this not true? If it is true, then either one will work, no? In fact,
if this is your only goal, the 20 Hz notch should be better.
--
% Randy Yates % "With time with what you've learned,
%% Fuquay-Varina, NC % they'll kiss the ground you walk
%%% 919-577-9882 % upon."
%%%% <yates@[EMAIL PROTECTED]
> % '21st Century Man', *Time*, ELO
http://www.digitalsignallabs.com
|
